160k views
5 votes
A student is holding a watermelon off of the Empire state building in NYC. He drops it off the side. After 4.25 secs, how far did the watermelon travel?

User TysonSubba
by
8.2k points

1 Answer

3 votes

Final answer:

The watermelon traveled approximately 88.725 meters after 4.25 seconds of falling.

Step-by-step explanation:

The distance traveled by the watermelon can be calculated using the formula for free fall: d = (1/2) * g * t^2, where d is the distance traveled, g is the acceleration due to gravity, and t is the time. In this case, we know that the watermelon has been falling for 4.25 seconds. The acceleration due to gravity on Earth is approximately 9.8 m/s^2. Substituting the given values into the formula, we get:

d = (1/2) * 9.8 m/s^2 * (4.25 s)^2

d = 1/2 * 9.8 m/s^2 * 18.0625 s^2

d = 88.725 m

Therefore, the watermelon traveled approximately 88.725 meters after 4.25 seconds of falling.

User Igorc
by
8.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories