Question

Given Tn = 2n + 2n^2 and Tn = log10^10, what is the sum of the first five terms?

Option 1: 590
Option 2: 615
Option 3: 640
Option 4: 665

Answer 1

To find the sum of the first five terms, substitute n = 1, 2, 3, 4, and 5 into the given expression Tn = 2n + 2n^2. The sum of the first five terms is 150.

Step-by-step explanation:

To find the sum of the first five terms, we need to substitute n = 1, 2, 3, 4, and 5 into the given expression Tn = 2n + 2n^2.

So, the first five terms are:

• T1 = 2(1) + 2(1^2) = 4
• T2 = 2(2) + 2(2^2) = 12
• T3 = 2(3) + 2(3^2) = 24
• T4 = 2(4) + 2(4^2) = 40
• T5 = 2(5) + 2(5^2) = 70

The sum of these terms is: 4 + 12 + 24 + 40 + 70 = 150.

Therefore, none of the options given (590, 615, 640, 665) is the correct sum of the first five terms.