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A skater accelerates from rest to 5.35 m/s over 28.7 m. Determine the skater’s acceleration.

Options:
A. 0.186 m/s²
B. 0.371 m/s²
C. 0.372 m/s²
D. 0.747 m/s²

User Genpfault
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1 Answer

6 votes

Final answer:

The acceleration of the skater can be found using the kinematic equation, but the calculated value of 0.4986 m/s² does not match any of the provided options, indicating a possible error in the question or the options.

Step-by-step explanation:

To determine the skater's acceleration, we can use the kinematic equation for constant acceleration, which states:

v^2 = u^2 + 2as

Where,

  • v is the final velocity (5.35 m/s),
  • u is the initial velocity (0 m/s, since the skater starts from rest),
  • a is the acceleration,
  • s is the displacement (28.7 m).

Rearranging the equation for acceleration gives:

a = (v^2 - u^2) / (2s)

Plugging in the values:

a = (5.35^2 - 0^2) / (2 * 28.7)

a = (28.6225) / (57.4)

a = 0.4986 m/s²

This is not an option given in the multiple choices provided by the student, which suggests there might be a typo or mistake in the provided options or the question details. The student may need to check the question again for accuracy or discuss this discrepancy with their instructor.

User Samnoon
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8.1k points