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John drops a ball off a building and it bounces 20 feet on the first bounce. After that, it bounces 50% of its original height. How high does it bounce on the 6th bounce?

A. 2.5 feet
B. 10 feet
C. 5 feet
D. 0.625 feet

1 Answer

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Final answer:

To calculate the height of the 6th bounce when the ball bounces at 50% of its previous height each time, we use the formula for a geometric sequence. The height of the 6th bounce is 0.625 feet.

Step-by-step explanation:

When John drops a ball off a building and it bounces 20 feet on the first bounce, and then bounces 50% of its original height on subsequent bounces, we can use a geometric progression to find the height of the 6th bounce.

The height of the bounce can be found using the formula height of the nth bounce = initial height × (bounce factor)n-1, where bounce factor is 0.5 for 50% of the height.

So, the height of the 6th bounce would be 20 × (0.5)6-1 = 20 × (0.5)5 = 20 × 0.03125 = 0.625 feet. Therefore, the answer is D. 0.625 feet.

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