Question

A ball rolled 12.0m [E] in 10.0s, hit an obstacle, and rolled straight back.

After the collision, the ball rolled 8.00m [W] in 6.00s. What was the average velocity of the ball?
A) 0.250m/s [E]
B) 1.25m/s
C)1.25m/s [E]
D) 0.250m/s

Answer 1

The correct answer to the question is A) 0.250 m/s [E], as the total eastward displacement of the ball is 4.0 m and the total time taken is 16.0 s, resulting in an average velocity of 0.250 m/s to the east.

Step-by-step explanation:

The question indicates that a ball rolls 12.0 m east (E), hits an obstacle, then rolls 8.0 m west (W) in differing times. To find the average velocity of the ball, we consider the total displacement and the total time taken. Displacement is a vector quantity, meaning it has both magnitude and direction. The ball's eastward displacement is 12.0 m and its westward displacement is -8.0 m (as west is the opposite direction to east, it's considered negative in this context). The total displacement is therefore:

12.0 m (E) - 8.0 m (W) = 4.0 m (E)

The total time for both parts of the journey is:

10.0 s + 6.0 s = 16.0 s

Therefore, the average velocity is:

Average velocity = Total displacement / Total time

= 4.0 m (E) / 16.0 s

= 0.250 m/s [E]

Among the options given, A) 0.250 m/s [E] is the correct answer.