Final answer:
The percentage of the original radioactive parent that is left after one year is 90.2%.
Step-by-step explanation:
The percentage of the original radioactive parent that is left after one year can be determined by understanding the concept of half-life. For cobalt-60, which has a half-life of 5.27 years, 50% remains after one half-life, 25% remains after two half-lives, and so on. Since one year is less than the half-life of cobalt-60, it is less than one half-life, and therefore more than 50% of the original radioactive parent will be left. The correct answer is A) 90.2%.