Question

Alice, Kathy, and Sheila work at the office together. Alice has worked 8 years longer than Kathy. Kathy has worked half as long as Sheila. If Sheila has worked at the company for 10 years, how many years has Alice worked there?

A) 14 years
B) 16 years
C) 18 years
D) 20 years

Answer 1

To determine Alice's years of service, we calculated that Kathy has worked for 5 years, as she has worked half as long as Sheila, who has worked 10 years. Adding 8 years to Kathy's duration, we get 13 years for Alice, which does not match any of the given answer choices, indicating a possible error.

Step-by-step explanation:

The subject of the question is Mathematics, and it is typically appropriate for Middle School level.

Since Sheila has worked for 10 years, and we know that Kathy has worked for half as long as Sheila, we can calculate Kathy's years of service as follows:

Kathy's years = Sheila's years / 2 = 10 years / 2 = 5 years.

Alice has worked 8 years longer than Kathy, so to find out how many years Alice has worked there, we add those 8 years to Kathy's years of service:

Alice's years = Kathy's years + 8 years = 5 years + 8 years = 13 years.

However, there is no option for 13 years in the given choices, which indicates there may be an error in the question or the options provided. We may need to double-check the question details or reach out for clarification.