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Order the set of numbers from least to greatest: 200, 14, 41, 3/5

A) 3/5, 14, 41, 200
B) 200, 41, 14, 3/5
C) 3/5, 41, 14, 200
D) 14, 3/5, 41, 200

User Gotube
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1 Answer

2 votes

Final Answer:

The ordered set from least to greatest is option A) 3/5, 14, 41, 200.

Thus option a is correct.

Step-by-step explanation:

To order these numbers from least to greatest, let's analyze each value. We have 200, 14, 41, and 3/5. Comparing them, we see that 3/5 is the smallest as it is a fraction less than 1. Next, 14 is smaller than both 41 and 200. Finally, comparing 41 and 200, 41 is smaller than 200. So, the correct order is 3/5, 14, 41, 200.

Comparing these numbers is straightforward. Starting with the smallest, 3/5 is less than 1 and hence is smaller than all other whole numbers listed. Moving on, 14 is smaller than both 41 and 200. Finally, comparing 41 and 200, 41 is smaller. Therefore, arranging these values in ascending order results in 3/5, 14, 41, 200, as listed in option A.

The ordering is determined by comparing the values from least to greatest. The fractional value 3/5 is the smallest as it is less than 1, followed by 14, which is smaller than both 41 and 200. Lastly, 41 comes before 200. This sequence, from least to greatest, corresponds to option A) 3/5, 14, 41, 200.

Therefore option a is correct.

User Kreempuff
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