Final answer:
The quadratic equation x^2 - 6x = 58 can be solved by using the quadratic formula. The solutions are found to be x = 3 + √67 and x = 3 - √67. None of the options given are correct.
Step-by-step explanation:
Let's solve the quadratic equation x^2 - 6x = 58 by first bringing it into the standard quadratic form ax^2 + bx + c = 0. To do this, we subtract 58 from both sides, resulting in x^2 - 6x - 58 = 0.
Now we use the quadratic formula, -b ± √b^2 - 4ac / 2a, to find the solutions. Here, a = 1, b = -6, and c = -58. Plugging these values into the quadratic formula, we get:
x = (-(-6) ± √((-6)^2 - 4(1)(-58))) / (2(1))
x = (6 ± √(36 + 232)) / 2
x = (6 ± √268) / 2
x = (6 ± √(4×67))) / 2
x = (6 ± 2√67) / 2
x = 3 ± √67
Therefore, the solutions of the quadratic equation are x = 3 + √67 and x = 3 - √67, which means none of the provided options are correct.