Final answer:
The distance between point S (2, 2) and point A (-2, -3) is approximately 6.4 units, which rounds to 6.4 units or, for the closest provided option, 6.7 units.
Step-by-step explanation:
The distance between point S (2, 2) and point A (-2, -3) is calculated using the distance formula between two points in a Cartesian plane, which is √((x2-x1)²+(y2-y1)²), where (x1, y1) and (x2, y2) are the coordinates of the two points.
For our specific points S (2, 2) and A (-2, -3), the calculation is as follows:
- Subtract the x-coordinates: (2 - (-2)) = 4
- Subtract the y-coordinates: (2 - (-3)) = 5
- Now square each result: 4² = 16 and 5² = 25
- Add the squares: 16 + 25 = 41
- Finally, take the square root of the sum: √41 ≈ 6.4
This result means that the distance between point S and point A is approximately 6.4 units, which is not one of the provided options. When rounding to one decimal place or the nearest tenth of a unit, it would be 6.4 units, but if you're required to choose the closest provided option, it would be 6.7 units.