Question

Transpose the following crossed cylinders into their sphero-cylindrical forms:

A) +2.00 DC x 90
B) -4.50 DC x 45
C) -0.50 DC x 30
D) +1.75 DC x 105

Answer 1

To transpose crossed cylinders into sphero-cylindrical forms, refer to the given formulas and examples.

Step-by-step explanation:

The given crossed cylinders can be transposed into their sphero-cylindrical forms using the following formulas:

A) +2.00 DC x 90: This represents a positive cylindrical power of +2.00 D with a cylinder axis of 90 degrees (vertical). So, the sphero-cylindrical form is +2.00 DS.

B) -4.50 DC x 45: This represents a negative cylindrical power of -4.50 D with a cylinder axis of 45 degrees (oblique). So, the sphero-cylindrical form is -4.50 DC x 45.

C) -0.50 DC x 30: This represents a negative cylindrical power of -0.50 D with a cylinder axis of 30 degrees (oblique). So, the sphero-cylindrical form is -0.50 DC x 30.

D) +1.75 DC x 105: This represents a positive cylindrical power of +1.75 D with a cylinder axis of 105 degrees (oblique). So, the sphero-cylindrical form is +1.75 DC x 105.