Final answer:
Using the kinematic equations of motion, the maximum distance reached by a bowling ball thrown by the Incredible Hulk with an initial velocity of 106.6 m/s and decelerating at -6.3 m/s² is approximately 901.7 meters.
Step-by-step explanation:
The question involves calculating the maximum distance a bowling ball would travel when thrown with an initial speed and subject to a decelerating force. To find the distance, we'll use the kinematic equation for motion under constant acceleration, which is s = vt - 0.5at², where s is the distance, v is the initial velocity, a is the acceleration, and t is time.
Since the Incredible Hulk does the throwing, his strength imparts an initial velocity of 106.6 m/s to the bowling ball. The ball then decelerates at a = -6.3 m/s² until it stops. We need to first calculate the time it takes for the bowling ball to stop by using the equation v = u +at where v is the final velocity (which is 0 when the ball stops), u is the initial velocity, and a is the acceleration. After finding the time, we will plug it into the distance equation to calculate the maximum distance traveled by the ball.
Following the calculation:
- The time it takes for the bowling ball to come to a stop:
t = -v / a = -106.6 m/s / (-6.3 m/s²) = 16.92 s - Now, using the time to find the distance:
s = vt - 0.5at²
s = 106.6 m/s * 16.92 s - 0.5 * (-6.3 m/s²) * (16.92 s)²
s = 1802.392 - (0.5 * 6.3 * 286.1664)
s = 1802.392 - 900.3172
s = 901.67 m
Thus, the maximum distance the bowling ball will reach if it is accelerating at -6.3 m/s² is approximately 901.7 meters, rounding to one decimal place.