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The combustion of 2.208 g of propanol (C₃H₇OH) increases the temperature of a bomb calorimeter from 298.00 K to 302.56 K. The heat capacity of the bomb calorimeter is 16.25 kJ/K . Determine Δ for the combustion of propanol to carbon dioxide gas and liquid water.

User Jkteater
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Final answer:

To find the ΔH for the combustion of propanol, we multiply the heat capacity of the calorimeter by the change in temperature, divide this value by the mass of propanol combusted, and then multiply by the molar mass of propanol to get the enthalpy change per mole.

Step-by-step explanation:

To determine the ΔH for the combustion of propanol to carbon dioxide gas and liquid water, we can use the temperature change measured by the bomb calorimeter and its heat capacity. The formula for calculating the heat (q) involved in the combustion is q = C₂ᴇₜ(Tₒ - T₁), where C₂ᴇₜ is the heat capacity of the calorimeter, Tₒ is the final temperature, and T₁ is the initial temperature. Using the provided data, q = 16.25 kJ/K × (302.56 K - 298.00 K).

Next, we can calculate the amount of heat released per gram of propanol by dividing the calculated heat by the mass of the propanol combusted. Finally, to determine ΔH per mole, we multiply this value by the molar mass of propanol. Since we are looking for the enthalpy change (ΔH), we must represent the final value as negative because combustion is an exothermic process, releasing heat to the surroundings.

User Kalitsov
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