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How long would it take a bungee jumper to drop straight down from rest, from a height of 50.0m ignoring any air resistance? (g=9.80m/s​)

User VishuB
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1 Answer

7 votes

Final answer:

A bungee jumper dropping from a 50.0m height with no air resistance would take approximately 3.19 seconds to reach the ground.

Step-by-step explanation:

To calculate how long it would take for a bungee jumper to drop straight down from a height of 50.0m without air resistance, we use the formula for the time of free fall under the constant acceleration due to gravity. The formula is derived from the equation of motion under constant acceleration, which is:

s = ut + ½at²

where:

  • s is the distance fallen (50.0m)
  • u is the initial velocity (0 m/s, as the jumper starts from rest)
  • a is the acceleration due to gravity (9.80 m/s²)
  • ½ is a constant fraction
  • t is the time in seconds

Since the initial velocity, u, is 0 m/s, our formula simplifies to:

s = ½at²

By rearranging the formula to solve for time, t, we get:

t = sqrt(2s/a)

We can now plug in the values:

t = sqrt(2 * 50.0m / 9.80 m/s²) = sqrt(10.20408) ≈ 3.19 seconds

Therefore, it would take the bungee jumper approximately 3.19 seconds to drop from a height of 50.0m, assuming no air resistance.

User Boisterouslobster
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