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Y=7500(1+0.3)^x what is the initial value

Option 1: 7500
Option 2: 2250
Option 3: 10000
Option 4: 0

User Wendellmva
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1 Answer

5 votes

Final answer:

The initial value of the function y=7500(1+0.3)^x is 7500, which is found by setting x to zero in the equation, simplifying it to y = 7500(1).

Step-by-step explanation:

The initial value of the function y=7500(1+0.3)^x is identified by determining the value of y when x is zero since the initial value corresponds to the y-intercept of the function, which is the value of y before any changes are applied (i.e., when the x-value is 0). In the equation presented, setting x to zero gives us:

y = 7500(1+0.3)^0

Since any number to the power of zero is 1, we simplify the equation to:

y = 7500(1)

Thus, the initial value is 7500.

User Elegant
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