Answer:
411.88 N
Step-by-step explanation:
Given that:
mass of satellite m = 1847 kg
mass of the earth M = 5.97 × 10²⁴ kg
centripetal acceleration a = 0.223 m/s²
The magnitude of the force exerted by the earth on the satellite = the centripetal force that is being exerted by the satellite.
∴
![m (v^2)/(r) = G (mM)/(r^2)](https://img.qammunity.org/2022/formulas/physics/college/ob2c34rk5cpe1m4dr1nejx292t00u0td2v.png)
![ma = G (mM)/(r^2)](https://img.qammunity.org/2022/formulas/physics/college/2gc1zcfxad70wd1rr2smseszhvic0wmzqb.png)
![G (mM)/(r^2)= 1847 * 0.223](https://img.qammunity.org/2022/formulas/physics/college/aogqj0r2fpsea3z0c07n2frljivdtduvef.png)
![G (mM)/(r^2)= 411.88 \ N](https://img.qammunity.org/2022/formulas/physics/college/snhi8tctmjawkctr7kubetd3k51tm7v0rr.png)