Final answer:
The equation appears to be of a horizontal line y=52, which would mean a line parallel to it through point (-2, 1) should also be horizontal. Therefore, the equation of the desired line is y = 1, as it must maintain the same y-value to be parallel.
Step-by-step explanation:
The objective is to find the equation of a line parallel to the given line y = 50 + 2 which seems to imply y = 52 due to a potential typo, and which passes through the point (-2, 1). Since no slope value is given and we are encountering a discrepancy in the provided equation, we will assume a typo occurred and we should reference the common knowledge that a line with equation y = c where c is a constant, is a horizontal line with a slope of 0. Lines parallel to it would also have a slope of 0. Thus the slope-intercept form of the line we are looking for would be y = b. Because it passes through the point (-2, 1), and y must always equal 1 for it to be parallel to the line y = 52, the equation for the line is y = 1.
If, however, the actual intention was to provide a slope (which due to the typos, was not included), we could then write the slope-intercept form as y = mx + b where m is the slope and b is the y-intercept. Without the correct slope information, we cannot provide options like A, B, C, or D given in the original question. Thus, it is essential to resolve the discrepancy in the question to proceed.