Final answer:
In both absorption and emission spectroscopy, c) the energy of the photon is equal to the energy difference between the levels involved.
Step-by-step explanation:
In both absorption and emission spectroscopy, the energy of the photon is equal to the energy difference between the levels involved in a particular electronic transition. During absorption spectroscopy, when an electron moves from a lower energy level to a higher one, it absorbs a photon with energy equal to the energy difference between the levels. On the other hand, in emission spectroscopy, when an electron moves from a higher energy level to a lower one, it emits a photon with energy equal to the energy difference between the levels.