Final answer:
The probability that a randomly selected student will score 70 or higher on the final exam is approximately 16%, which corresponds to Option A.
Step-by-step explanation:
To find the probability that a randomly selected student will score 70 or higher on a statistics final exam with a mean (μ) of 65 and a standard deviation (σ) of 5, we will use the properties of the normal distribution.
First, we calculate the z-score for a score of 70:
Z = (X - μ) / σ
Z = (70 - 65) / 5
Z = 1
A z-score of 1 indicates that a score of 70 is one standard deviation above the mean. Since the normal distribution is symmetric, the area to the left of z = 1 is 0.8413 (or 84.13%). Therefore, the area to the right of z = 1, which represents the probability of scoring higher than 70, is 1 - 0.8413, which equals 0.1587 or approximately 16%.
This information gives us the answer: Option A) 16%