123k views
3 votes
An aircraft has a liftoff speed of 33 m/s. What minimum constant acceleration does this require if the aircraft is to be air borne after a take-off run of m?

a) +2.3 m/s²
b) +3.5 m/s²
c) +4.9 m/s²
d) +5.7 m/s²

User Arun Ghosh
by
7.6k points

1 Answer

1 vote

Final answer:

Without the take-off run distance, we cannot determine the specific acceleration required for an aircraft to reach a liftoff speed of 33 m/s. The kinematic equation v^2 = u^2 + 2as is used if the distance were known.

Step-by-step explanation:

The question is asking for the minimum constant acceleration needed for an aircraft to reach a liftoff speed of 33 m/s given a certain take-off run distance that is presumably provided but missing in the question. To find this acceleration, one can use the kinematic equation: v^2 = u^2 + 2as, where v is the final velocity (33 m/s), u is the initial velocity (0 m/s, as the aircraft starts from rest), a is the acceleration, and s is the displacement (take-off run). However, since the take-off run distance is not provided in the question, we cannot calculate a specific acceleration value. If the distance were given, we could rearrange the equation to solve for a and calculate the required acceleration.

User Steve Heim
by
8.2k points