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If the radius of the circle along which the bowling moose is a 1.2 m are in the acceleration is 7.5 m/s², what is the speed of the ball?

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Final answer:

The speed of the ball for which the bowling moose is 1.2 m is in the acceleration is 7.5 m/s² is 3 m/s.

Step-by-step explanation:

We will be using the formula of centripetal acceleration to find the speed of the ball.

Centripetal acceleration is measured using the formula:

a = v²/r

Where a denotes acceleration, v denotes the speed, and r denotes the radius of the circle. Rearranging the formula, we get:

v = sqrt(a * r)

Plugging in the values, we have:

v = sqrt(7.5 * 1.2)

= sqrt(9)

= 3 m/s

So, the speed of the ball is 3 m/s.

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