Question

There were 390 people at a play the admission price was 2$ for adults and 1 for children the admission recepts were 610 how many adults and how children attend.

Answer 1

To solve this problem, we can set up a system of equations. Let A represent the number of adults and C represent the number of children. From the given information, we can set up two equations: A + C = 390 and 2A + C = 610. Solving this system of equations, we find that there were 220 adults and 170 children in attendance at the play.

Step-by-step explanation:

To solve this problem, we can set up a system of equations using the given information. Let's assume that the number of adults attending the play is represented by 'A', and the number of children attending is represented by 'C'.

From the given information, we can set up two equations:

1. A + C = 390 (equation 1)
2. 2A + C = 610 (equation 2)

We can solve this system of equations by first multiplying equation 1 by 2 and subtracting equation 2 from the result:

• 2A + 2C = 780
• -(2A + C) = -610
• --------------------------
• C = 170

Substituting the value of C into equation 1, we can solve for A:

• A + 170 = 390
• A = 390 - 170
• A = 220

Therefore, there were 220 adults and 170 children in attendance at the play.