Question

A flea of mass 0.8 mg jumps directly vertically, reaching a height 26 cm above its starting position. How much work (in μJ) did the flea's legs do to accelerate the flea?

Answer 1

The work done by the flea's legs to accelerate the flea is 0.2 μJ.

Step-by-step explanation:

To calculate the work done by the flea's legs to accelerate the flea, we first need to determine the change in gravitational potential energy. The work done by the flea's legs is equal to the change in gravitational potential energy.

Gravitational potential energy (PE) = mgh, where m is the mass of the flea, g is the acceleration due to gravity (9.8 m/s^2), and h is the height the flea reaches above its starting position.

Substituting the given values, we have: PE = (0.8 mg)(0.26) = 0.2 μJ.