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A 1.07 g sample of a Noble gas occupies a volume of 363 mL at 35°C and 678 mmHg. Identify the noble gas in this sample. (R = 0.08206 L'atm/K'mol)

a. He
b. Ne
c. Ar
d. Kr

1 Answer

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Final answer:

To identify the noble gas in the sample, we can use the ideal gas law equation PV = nRT. Rearranging the equation allows us to solve for the number of moles. By substituting the given pressure, volume, and temperature values into the equation, we can find the number of moles in the sample.

Step-by-step explanation:

To identify the noble gas in the sample, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can rearrange the equation to solve for the number of moles, n = PV / RT. First, convert the given temperature from degrees Celsius to Kelvin by adding 273.15, so T = 35°C + 273.15 = 308.15 K. Convert the given pressure from mmHg to atm by dividing by 760, so P = 678 mmHg / 760 = 0.892 atm. Finally, substitute the values into the equation n = (0.892 atm) * (363 mL) / ((0.08206 L.atm/K.mol) * (308.15 K)). Solve for n to find the number of moles in the sample.

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