Question

Un automóvil pasa por un puesto de vigilancia a 90 km por hora. A los cinco minutos de haber pasado el auto sale en su persecución una motocicleta a 120 km por hora. ¿Cuánto tiempo tardará la moto en alcanzar al auto?

Answer 1

In fifteen minutes, the motorcycle will overtake the automobile.

Speed and Distance

Using the specifications provided in our calculation;

Car's speed is 90 km/h.

Motorcycle speed: 120 km/h

Time × Speed = Distance

The distance an automobile traveled before a motorcycle pursued it;

Time at which the distance would remain the same: Distance = 90 × 5/60 = 7.5 km

Assume that d is the distance.

motorcycle distance minus automobile distance

d - 5/90 equals d/120.

multiplication by cross

90d - 120(d - 7.5)

90d is 120d - 900.

90d - 120d = 900

900 / 30d =

d is equal to 900/30.

d is equal to 30 km.

The amount of time required is equal to

Time is equal to distance traveled and speed.

Time = 120 km/h / 30 km

Time: 0.25 hours (0.25 times 60) minus fifteen minutes

Thus, in fifteen minutes, the motorcycle will overtake the automobile.

Answer 2

The motorcycle will catch up with the car after 15 minutes

Using the parameters given for our Calculation;

• Speed of car = 90 km/hr
• Speed of motorcycle = 120 km/hr

Distance = Speed × time

Distance moved by car before motorcycle gave chase;

• Distance = 90 × 5/60 = 7.5 km

Time when Distance would be the same ;

• Let the distance = d

car distance = motorcycle distance

d - 5/90 = d/120

cross multiply

120(d - 7.5) = 90d

120d - 900 = 90d

120d - 90d = 900

30d = 900

d = 900/30

d = 30 km

The time taken is equivalent to ;

• Time = Distance/ speed

Time = 30km / 120km/hr

Time = 0.25 hour (0.25 × 60) ≈ 15 minutes

Therefore , the motorcycle will catch up with the car after 15 minutes.