Final answer:
The mass of chloride in grams present in 100 mL of a 0.25 M solution of GaCl3 (gallium(III) chloride) is 0.885 g.
Step-by-step explanation:
To determine the mass of chloride in grams present in 100 mL of a 0.25 M solution of GaCl3 (gallium(III) chloride), we need to first calculate the number of moles of GaCl3 present in the solution. The molarity of a solution is defined as the number of moles of solute per liter of solution. So, for a 0.25 M solution of GaCl3, the number of moles of GaCl3 can be calculated as:
0.25 mol/L x 0.100 L = 0.025 mol of GaCl3
Next, we can use the molar mass of chloride (35.45 g/mol) to convert the moles of GaCl3 to grams of chloride:
0.025 mol x 35.45 g/mol = 0.885 g