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Find the components of the average acceleration during the time interval from t0 = 5.00 s to tz = 9.00 s.

A. Vx = 0.75 m/s², Vy = -1.00 m/s²
B. Vx = -0.75 m/s², Vy = 1.00 m/s²
C. Vx = 1.50 m/s², Vy = -2.00 m/s²
D. Vx = -1.50 m/s², Vy = 2.00 m/s²

User Fredmat
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Final answer:

To find the components of average acceleration, calculate the change in velocity (\(ΔV\)) in the x and y-directions over the given time interval. For this scenario, the components are (A_x = 0.75 \, \text{m/s}^2) and (A_y = -1.00 \, \text{m/s}^2). These represent the average accelerations in the x and y-directions, respectively.

Step-by-step explanation:

To find the components of average acceleration, we need to calculate the change in velocity in the x-direction (ΔVx) and the change in velocity in the y-direction (ΔVy) over the given time interval. The average acceleration in the x-direction (Ax) is equal to ΔVx / Δt, where Δt is the change in time. Similarly, the average acceleration in the y-direction (Ay) is equal to ΔVy / Δt. In this case, the change in velocity in the x-direction (ΔVx) is Vx at t = tz - Vx at t = t0, and the change in velocity in the y-direction (ΔVy) is Vy at t = tz - Vy at t = t0. Therefore, the components of average acceleration are A. Vx = 0.75 m/s², Vy = -1.00 m/s².

User Rohit Ghotkar
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