55.3k views
5 votes
Given the equation y = 4/3x + 7, write the equation of a line through (-6,10) that is parallel to the line given above. What is the equation of the parallel line?

a) y = 4/3x - 10
b) y = -4/3x - 7
c) y = 3/4x + 10
d) y = -3/4x - 10

User RobertsonM
by
8.1k points

1 Answer

2 votes

Final answer:

To find the equation of a line parallel to y = 4/3x + 7 and passing through (-6,10), we write the equation using the point-slope form. The equation of the parallel line is y = (4/3)x + 18.

Step-by-step explanation:

To find the equation of a line parallel to y = 4/3x + 7, we use the fact that parallel lines have the same slope. The given line has a slope of 4/3, so the parallel line will also have a slope of 4/3. Since the line passes through the point (-6,10), we can use the point-slope form of a linear equation to find the equation of the line:

y - y1 = m(x - x1)

Substituting the values into the equation, we get:

y - 10 = (4/3)(x - (-6))

y - 10 = (4/3)(x + 6)

y - 10 = (4/3)x + 8

y = (4/3)x + 8 + 10

y = (4/3)x + 18

Therefore, the equation of the line parallel to y = 4/3x + 7 and passing through (-6,10) is y = (4/3)x + 18, which corresponds to answer choice d).

User Dharam Mali
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories