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The relationship between altitude and boiling point of a liquid is linear. At an altitude of 8000 feet, the liquid boils at 202.4°F. At an altitude of 4700 feet, the liquid boils at 206.36°F. Write an equation giving the boiling point b of the liquid, in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2500 feet?

A) b = -0.0152a + 326.8; 201.6°F
B) b = -0.0152a + 326.8; 204.8°F
C) b = -0.0152a + 326.8; 207.4°F
D) b = -0.0152a + 326.8; 210.2°F

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Final answer:

The relationship between altitude and boiling point of a liquid is linear. The equation giving the boiling point b of the liquid in terms of altitude a is b = -0.0152a + 326.8. At an altitude of 2500 feet, the boiling point of the liquid is 204.8°F.

Step-by-step explanation:

The relationship between altitude and boiling point of a liquid is linear. In this case, we can use the equation of a line, y = mx + b, where y is the boiling point in degrees Fahrenheit, x is the altitude in feet, and m and b are constants. To find the equation, we can use the given data points: (8000, 202.4) and (4700, 206.36).

First, we need to find the slope, m, which is (change in y) / (change in x). m = (202.4 - 206.36) / (8000 - 4700) = -0.0152.

Next, we can use one of the data points and the slope to find the y-intercept, b, in the equation y = mx + b. Using (8000, 202.4), we get 202.4 = -0.0152 * 8000 + b. Simplifying, we find b = 326.8.

Therefore, the equation giving the boiling point b of the liquid in terms of altitude a is b = -0.0152a + 326.8. To find the boiling point at 2500 feet, we substitute a = 2500 into the equation: b = -0.0152 * 2500 + 326.8 = 204.8°F.

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