Final answer:
Substituting t = 2 seconds into the equation h = 64t - 16t^2 gives a height of 64 feet, which means the ball will be 64 feet above the ground after 2 seconds.
Step-by-step explanation:
To find the height of the ball after 2 seconds, we need to substitute t = 2 seconds into the given height equation, h = 64t - 16t^2. By substituting, we get: h = 64(2) - 16(2)^2, h = 128 - 16(4), h = 128 - 64, h = 64 feet. Therefore, the height of the ball after 2 seconds is 64 feet. This means that after 2 seconds, the height of the ball is 64 feet. The positive value indicates the height above some reference point. In summary, by substituting the given time into the height equation and performing the necessary calculations, we determine the height of the ball at the specified time.