74.1k views
0 votes
The following problem represents a population of bacteria. P(1)-350(2)ᵗ where t equals time in hours. How many bacteria are present after 0, 1, and 2 hours? How do you know that the growth is not linear?

A. After 0 hours: 350, After 1 hour: 700, After 2 hours: 1400; The growth is exponential, not linear.
B. After 0 hours: 350, After 1 hour: 400, After 2 hours: 450; The growth is linear.
C. After 0 hours: 0, After 1 hour: 350, After 2 hours: 700; The growth is linear.
D. After 0 hours: 350, After 1 hour: 750, After 2 hours: 1150; The growth is exponential, not linear.

User Lcat
by
7.7k points

1 Answer

6 votes

Final answer:

The number of bacteria present after 0, 1, and 2 hours is 350, 700, and 1400 respectively. The growth is exponential because the number of bacteria is increasing at an increasing rate.

Step-by-step explanation:

The problem represents a population of bacteria. The equation P(1)-350(2)ᵗ shows the number of bacteria present at different times, where t represents time in hours.

To find the number of bacteria present after 0, 1, and 2 hours, we substitute t=0, t=1, and t=2 into the equation. After 0 hours: 350 bacteria, after 1 hour: 700 bacteria, after 2 hours: 1400 bacteria.

The growth is exponential, not linear, because the number of bacteria is increasing at an increasing rate. In linear growth, the number of bacteria would increase by a constant amount at each time interval.

User Chenny
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories