Question

Glucose, CH_2O_6, is used as an energy source by the human body. The overall reaction in the body is described by the equation

CH_2O_6(aq) + 6O_2(g) → 6CO_2(g) + 6H_2O(l)

Calculate the number of grams of oxygen required to convert 33.0 g of glucose to CO_2 and H_2O.

Answer 1

To find the mass of oxygen needed to combust 33.0 g of glucose, we calculate the moles of glucose, find the stoichiometrically equivalent moles of oxygen, and then convert these to grams. The result is 35.13 grams of oxygen.

Step-by-step explanation:

Calculating Oxygen Required for Glucose Combustion

To calculate the number of grams of oxygen required to convert 33.0 g of glucose to CO2 and H2O, first, we need to determine the molar mass of glucose (C6H12O6) and oxygen (O2). The molar masses are 180.16 g/mol for glucose and 31.9988 g/mol for oxygen. According to the balanced chemical equation for the combustion of glucose:

C6H12O6(s) + 6 O2(g) → 6 CO2(g) + 6 H2O(l)

One mole of glucose reacts with 6 moles of oxygen. Using the molar ratios, we can calculate the amount of oxygen needed for the reaction as follows:

1. 
   
2. 
   
3. 
   

Therefore, 35.13 grams of oxygen are required to completely combust 33.0 g of glucose.