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Label the period, the frequency, and the phase shift then graph and highlight the first period. Y=2+sec(theta+3pi/4)

User Sundar
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Final answer:

To label the period, frequency, and phase shift for the function y=2+sec(theta+3pi/4), the period is 2pi, the frequency is 1/2pi, and the phase shift is 3pi/4. The graph can be obtained by shifting the graph of y=2+sec(theta) right by 3pi/4 units, and the first period is highlighted by using the range of theta from 0 to 2pi.

Step-by-step explanation:

To label the period, frequency, and phase shift for the equation y=2+sec(theta+3pi/4), we can rewrite it as y=2+sec(theta+(3pi/4)).

The period of sec(theta) is 2pi, so the period of sec(theta+(3pi/4)) is also 2pi.

The frequency is the reciprocal of the period, so the frequency is 1/2pi.

The phase shift is the value inside the parentheses in the equation, so the phase shift is 3pi/4.

To graph the equation, we can start by graphing y=2+sec(theta) and then shift the graph right by 3pi/4 units.

Highlighting the first period, we can use the range of theta from 0 to 2pi.

User Anirudh Ramanathan
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