Final answer:
The mass of A₁₂(SO₄)₃ produced is 174.5 g.
Step-by-step explanation:
To find the mass of A₁₂(SO₄)₃ produced, we need to use the concept of stoichiometry. According to the balanced equation 2 Al + 3 H₂SO₄ → A₁₂(SO₄)₃ + 3 H₂, the molar ratio between Al and A₁₂(SO₄)₃ is 2:1. We start by converting the mass of H₂SO₄ to moles:
50 g H₂SO₄ * (1 mol / 98 g) = 0.51 mol H₂SO₄
Since Al is in excess, all of the 0.51 mol H₂SO₄ will react and form an equal moles of A₁₂(SO₄)₃. Finally, we can convert the moles of A₁₂(SO₄)₃ to grams:
0.51 mol A₁₂(SO₄)₃ * (342.2 g / mol) = 174.5 g A₁₂(SO₄)₃