Final answer:
To calculate the final velocity of the box after 1.7 seconds of free fall, with no initial velocity, the equation v = g × t is used, with g being the acceleration due to gravity (9.8 m/s^2). Substituting the time into the equation gives v = 9.8 m/s^2 × 1.7 s = 16.66 m/s, indicating a downward velocity of 16.66 m/s when the box hits the ground.
Step-by-step explanation:
The student is inquiring about a physics problem related to motion under the influence of gravity, specifically asking for the final velocity of an object falling from rest. To calculate the velocity of a box dropped from a window after 1.7 seconds, we can use the equation for velocity in uniformly accelerated motion, where the acceleration due to gravity (g) is approximately 9.8 m/s2. The equation is:
v = g × t
where:
- v is the final velocity,
- g is the acceleration due to gravity (9.8 m/s2), and
- t is the time in seconds.
By substituting the given values into the equation, we get:
v = 9.8 m/s2 × 1.7 s = 16.66 m/s
The positive sign indicates the direction of acceleration, which is downwards. So, the final velocity when the box hits the ground is 16.66 m/s downward.