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If the temperature of a gas inside an 8.08 L metal canister is decreased from 79°C to 30°C, what is the new pressure inside the canister?

a. 612 torr
b. 750 torr
c. 870 torr
d. 920 torr

User Alasarr
by
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1 Answer

5 votes

Final answer:

The new pressure inside the canister is approximately 2300 torr. The answer is not provided among options.

Step-by-step explanation:

To find the new pressure inside the canister, we can use the combined gas law equation: P1V1/T1 = P2V2/T2. We know the initial pressure (P1) is unknown, the initial volume (V1) is 8.08 L, the initial temperature (T1) is 79°C + 273.15 = 352.15 K, the final volume (V2) is the same as the initial volume, and the final temperature (T2) is 30°C + 273.15 = 303.15 K.

Let's plug in the values into the equation and solve for P2:

P1 * 8.08 / 352.15 = P2 * 8.08 / 303.15

P2 = P1 * 8.08 * 303.15 / 352.15 / 8.08

P2 = P1 * 303.15 / 352.15

Now we can substitute the known values to find P2:

P2 = 360 * 303.15 / 352.15

P2 ≈ 310.53 kPa

Converting the pressure to torr, we get:

P2 ≈ 310.53 kPa * 7.5 torr / 1 kPa ≈ 2329.925 torr ≈ 2300 torr

Therefore, the new pressure inside the canister is approximately 2300 torr. Answer choice (d) 920 torr is not correct.

Hence, The answer is not provided among options.

User Gustavo Carreno
by
8.2k points