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What is the absolute value of 1 - i√3?
a) 1
b) √3
c) 2
d) 2√3

User Darkfeline
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1 Answer

4 votes

Final answer:

The absolute value of 1 - i√3 is 2.

Step-by-step explanation:

The absolute value of a complex number is equal to the distance between the complex number and the origin on the complex plane.

Let's find the absolute value of 1 - i√3:

We can write 1 - i√3 as a complex number in the form a + bi, where a represents the real part and b represents the imaginary part.

a = 1 and b = -√3

The absolute value is given by |a + bi| = √(a^2 + b^2)

Substituting the values, we get: |1 - i√3| = √((1)^2 + (-√3)^2) = √1 + 3 = √4 = 2

So, the absolute value of 1 - i√3 is 2.

User Spdrman
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