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Find the equation of the line in standard form that passes through the following points (6,-11) and (7,2).

a) 13x - y = -155
b) 13x + y = 155
c) 13x - y = 155
d) 13x + y = -155

1 Answer

2 votes

Final answer:

The equation of the line passing through the points (6, -11) and (7, 2) in standard form is neither a), b), c), nor d) based on the calculated slope and standard form procedure. The correct equation should be 13x - y = 89, which is not listed among the provided options.

Step-by-step explanation:

To find the equation of the line in standard form that passes through the points (6, -11) and (7, 2), we'll first calculate the slope (m) of the line using the formula:

m = (y2 - y1) / (x2 - x1)

Plugging in our points:

m = (2 - (-11)) / (7 - 6) = 13

With the slope known, pick one of the points, (6, -11), to write the point-slope form of the equation:

y - (-11) = 13(x - 6)

Expanding this:

y 11 = 13x - 78

Now, rearrange to standard form, Ax + By = C:

13x - y = 78 + 11

13x - y = 89

Depending on how we define 'standard form', we might consider multiplying the equation by -1 if the format requires A to be negative:

-13x + y = -89

None of the options provided by the student match our results. It's possible there is a mistake in either the calculation or the provided options. Ensure calculations are correct and ask the student to double-check the options given.

User Rredondo
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