Question

28Ni62 may be described as the most strongly bound nucleus because it has the highest B.E. per nucleon. Its neutral atomic mass is 61.928349 a.m.u..Find its mass defect, its total binding energy and binding energy per nucleon.Given, mass of neutron=1.008665amu mass of proton=1.007825amu 1amu=931.5MeV.​

Answer 1

To find the mass defect and binding energy of 28Ni62, we can use the given values of neutron and proton masses. The mass defect is the difference between the actual mass of the nucleus and the sum of the masses of its protons and neutrons. The binding energy is the energy required to break the nucleus into its constituent nucleons. By dividing the total binding energy by the number of nucleons, we can find the binding energy per nucleon.

Step-by-step explanation:

Given the mass of neutron=1.008665 amu and the mass of proton=1.007825 amu, we can calculate the mass defect of the nucleus 28Ni62. The mass defect is given by the difference between the actual mass of the nucleus and the sum of the masses of its protons and neutrons. For 28Ni62, the mass defect is:

Mass defect = (28 * 1.007825 amu + 62 * 1.008665 amu) - 61.928349 amu

Once we have the mass defect, we can calculate the total binding energy using the formula:

Total binding energy = mass defect * 931.5 MeV

To calculate the binding energy per nucleon, we divide the total binding energy by the number of nucleons:

Binding energy per nucleon = total binding energy / number of nucleons

Using the given values, we can compute the mass defect, total binding energy, and binding energy per nucleon for 28Ni62.