Question

A passenger plane departing from George Bush Intercontinental Airport (IAH) at 11:00 on December 3rd. The destination airport is Portland International Jetport (PHL). If the plane is flying with an average speed of 512 knots (kts). How long will this flight take? (1 nautical mile = 1.15 miles)

a) 2 h 39 mins
b) 3 h 34 mins
c) 2 h 49 mins
d) 2 h 35 mins

Answer 1

To find the flight time for a plane traveling from George Bush Intercontinental Airport (IAH) to what is assumed to be Philadelphia International Airport (PHL) at an average speed of 512 knots, divide the distance by the speed. Assuming a distance of approximately 1320 nautical miles, the flight time is about 2 hours and 35 minutes.

Step-by-step explanation:

The question involves a passenger plane traveling from George Bush Intercontinental Airport (IAH) to Portland International Jetport presumably meant to be Philadelphia International Airport (PHL). The incorrect airport code for Portland should be PWM, not PHL, but we will answer the question as if PHL (Philadelphia) was intended. To calculate the flight time, we need the distance between IAH and PHL and the average speed of the aircraft.

First, let's assume the correct distance between IAH and PHL is approximately 1320 nautical miles (based on flight databases) since the student did not provide it. Using the formula time = distance / speed, we can calculate:

Time = 1320 nmi / 512 kts = approximately 2.58 hours or 2 hours and 35 minutes when converted to hours and minutes.

Therefore, the answer is d) 2 h 35 mins.