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If 1.25L of gas exists at 35∘C with a constant pressure of 0.70 atm in a cylindrical block and the volume were to be changed to 0.75L, what is the new temperature of the gas?

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Final answer:

The new temperature of the gas is 1.44°C.

Step-by-step explanation:

To find the new temperature of the gas when the volume is changed from 1.25L to 0.75L, we can use the combined gas law.

The combined gas law is given by the equation:

P1V1/T1 = P2V2/T2

Where P1 and T1 are the initial pressure and temperature, V1 is the initial volume, P2 is the final pressure, V2 is the final volume, and T2 is the final temperature.

In this case, the initial pressure is 0.70 atm, the initial volume is 1.25L, the final volume is 0.75L, and we need to find the final temperature.

Plugging in these values into the combined gas law equation and solving for T2:

0.70 atm × 1.25L / (35°C + 273.15) = 0.70 atm × 0.75L / T2

Simplifying, we get:

(0.70 atm × 1.25L × T2) / 308.15K = 0.70 atm × 0.75L

Cross multiplying and solving for T2:

T2 = (0.70 atm × 0.75L × 308.15K) / (0.70 atm × 1.25L)

T2 = 1.44

Therefore, the new temperature of the gas is 1.44°C.

User Anton Prokofiev
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