Question

A buried IED (improvised explosive device) goes off. 10 kg of metal flies north at 4 m/s. 100 kg of metal flies east at 2 m/s. 5 kg of metal flies south at 8 m/s, and 1 kg of metal flies west at 200 m/s. The total momentum after the explosion is:

A) 810 kg m/s
B) 710 kg m/s
C) 8100 kg m/s
D) 7010 kg m/s

Answer 1

The total momentum after the explosion is 0 kg m/s.

Step-by-step explanation:

To calculate the total momentum after the explosion, we need to consider both the mass and velocity of each piece of metal. The momentum of an object is given by the equation p = mv, where p is momentum, m is mass, and v is velocity.

For the 10 kg piece of metal flying north, the momentum is 10 kg * 4 m/s = 40 kg m/s.

For the 100 kg piece of metal flying east, the momentum is 100 kg * 2 m/s = 200 kg m/s.

For the 5 kg piece of metal flying south, the momentum is 5 kg * (-8 m/s) = -40 kg m/s (negative because it is moving in the opposite direction).

For the 1 kg piece of metal flying west, the momentum is 1 kg * (-200 m/s) = -200 kg m/s (negative because it is moving in the opposite direction).

To find the total momentum, we add up all the individual momenta: 40 + 200 + (-40) + (-200) = 0 kg m/s.