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What is the equation of the line that passes through the point (1,3) and has a slope of 66?

a) y = 66x - 63
b) y = 66x + 3
c) y = 66x - 63
d) y = 66x + 63

1 Answer

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Final answer:

The correct equation for the line that passes through the point (1,3) with a slope of 66 is y = 66x - 63.

Step-by-step explanation:

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Given that the line passes through the point (1,3) and has a slope of 66, we can substitute these values into the equation to find b. Using the point (1,3), the equation becomes 3 = 66(1) + b, which simplifies to 3 = 66 + b. Subtracting 66 from both sides gives us b = 3 - 66, so b = -63. Therefore, the equation of the line is y = 66x - 63.

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