Question

If you wanted to linearize the exponential equation N = Ce^(Kt), what would you graph on the vertical axis after taking the natural log of the equation?

A) ln(N)
B) ln(C)
C) Kt
D) N

Answer 1

When linearizing the exponential equation N = Ce^(Kt), you would graph ln(N) on the vertical axis to get a straight line, which represents the linear form of the equation y = mx + b.

Step-by-step explanation:

If you wanted to linearize the exponential equation N = CeKt, after taking the natural log of both sides of the equation, you would graph ln(N) on the vertical axis. When you take the natural logarithm of the equation, you get ln(N) = ln(C) + Kt. This is of the form y = mx + b, which represents a straight line with y equivalent to ln(N), m (the slope) equivalent to K, x equivalent to time t, and b (the y-intercept) corresponding to ln(C).