Final answer:
The concentration of hydrogen ions in pure water is 1 × 10-7 M, and the pH of pure water is 7.0. The concentration of hydrogen ions in rainwater is 3.16 × 10-6 M, and the pH of rainwater is 5.5.
Step-by-step explanation:
The concentration of hydrogen ions dissociating from pure water is 1 × 10-7 moles H+ ions per liter of water. The pH is calculated as the negative of the base 10 logarithm of this concentration. The log10 of 1 × 10-7 is -7.0, and the negative of this number yields a pH of 7.0, which is also known as neutral pH.
The pH of rainwater is 5.5. To calculate the concentration of hydrogen ions in moles per liter (M), we use the formula pH = -log10 [H+]. Rearranging the formula, we get [H+] = 10-pH. Substituting the pH value of 5.5, we get [H+] = 10-5.5 = 3.16 × 10-6 M.