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Suppose a new group 7A element is discovered. Photoelectron spectroscopy (PES) reveals that its last two peaks occur at 1610 kJ/mol and 1053 kJ/mol. Calculate the average valence electron energy (AVEE) of this element.

Option 1: 1331.5 kJ/mol
Option 2: 1331 kJ/mol
Option 3: 1330.5 kJ/mol
Option 4: 1330 kJ/mol

User Ardget
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1 Answer

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Final answer:

The average valence electron energy (AVEE) for the new element is calculated by averaging the last two peak energies given by photoelectron spectroscopy, which results in 1331.5 kJ/mol, corresponding to Option 1.

Step-by-step explanation:

To calculate the average valence electron energy (AVEE) of a new Group 7A element based on its photoelectron spectroscopy (PES) data, we use the energies of the last two peaks. The given values are 1610 kJ/mol and 1053 kJ/mol. To find the average, we add the two values together and divide by 2, which gives us:

AVEE = (1610 kJ/mol + 1053 kJ/mol) / 2

AVEE = 2663 kJ/mol / 2

AVEE = 1331.5 kJ/mol

Therefore, the correct answer is Option 1: 1331.5 kJ/mol.

User Etherice
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