1.0k views
4 votes
A parabola opening up or down has a vertex of (-3,4) and passes through (10, -89/20). Write its equation in vertex form. Simplify any fractions.

User Ucarion
by
8.0k points

1 Answer

4 votes

Final answer:

The equation of the parabola with a vertex at (-3,4) and passing through (10, -89/20) is y = (-1/20)(x + 3)^2 + 4.

Step-by-step explanation:

The parabola with a vertex at (-3,4) and passing through the point (10, -89/20) can be written in the vertex form of a quadratic equation,

which is y = a(x - h)^2 + k,

where (h,k) is the vertex of the parabola.

To find the value of 'a', we use the point (10, -89/20) that lies on the parabola.

Substituting the point into the vertex form, we get -89/20 = a(10 - (-3))^2 + 4.

Solving for 'a' gives us a = (-89/20 - 4) / (10+3)^2.

Simplifying this, we get a = (-89/20 - 80/20) / 169,

which further simplifies to a = -169/20 / 169, resulting in a = -1/20.

Thus, the equation of the parabola is y = (-1/20)(x + 3)^2 + 4, which is in vertex form.

User Matthew Arkin
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories