Final answer:
The total volume of the 3 goldfish is found by adding the increase in the tank's volume due to the displacement caused by the goldfish to the original volume of the tank. Since the volume increased by 1 cm evenly across the tank's base after adding the goldfish, the correct answer is the original tank volume plus the volume change, which is Option b) 9,003 cm³.
Step-by-step explanation:
To find the total volume of the 3 goldfish, we can use the information that the water level in the tank rose by 1 cm. The original volume of the tank is 9,000 cm³, and assuming the rise in water level is uniform across the entire tank, the increase in volume due to the goldfish is the area of the tank's base multiplied by the rise in water level. Without the tank's base area, we can assume the tank has a square base for simplicity, which means the total volume of the goldfish would be the area of the base times the height the water level rose.
Since we don’t have the area of the base, but we know the volume of water rose evenly by 1 cm, we simply calculate the new volume by adding the change in volume (the tank's cross-sectional area times the 1 cm rise) to the original volume:
Original volume of tank + increase in volume = 9,000 cm³ + (tank's cross-sectional area × 1 cm)
The increase in volume is essentially the total volume displaced by the goldfish, which is the volume of one goldfish times three. Therefore, if the water rose 1 cm evenly across the base, the total volume displaced, and thus the volume of the 3 goldfish, would be:
9,000 cm³ + (tank's cross-sectional area × 1 cm) which simplifies to 9,000 cm³ + (1 cm³ × tank's cross-sectional area) since the cross-sectional area in cm² multiplied by 1 cm will give us cm³.