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A veterinarian orders a 10-day supply of antibiotics to be dispensed to the owner of a 50-lb (22.7-kg) dog. If the dosage is 10 mg/lb (22 mg/kg) of body weight b.i.d., how many 250-mg tablets must be dispensed?

A. 10
B. 20
C. 40
D. 50

User JochenJung
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1 Answer

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Final answer:

A 50-lb dog needs to be given a 10-day course of antibiotics at 10 mg/lb b.i.d. (twice a day). At this dosage, the dog should receive a total of 10,000 mg over the course of the treatment, which means 40 of the 250-mg tablets need to be dispensed.

Step-by-step explanation:

The question is asking to calculate the total number of 250-mg antibiotic tablets required for a 50-lb (22.7-kg) dog that needs a dosage of 10 mg/lb b.i.d. (twice a day) for a 10-day course. First, we calculate the daily dosage in milligrams:

Daily dosage = 10 mg/lb × 50 lbs = 500 mg per day.

Since the medication needs to be given twice a day, the total daily mg would be:

Total daily dosage = 500 mg × 2 = 1000 mg per day.

Now, we determine how many days worth of medication is needed:

Total medication needed for 10 days = 1000 mg/day × 10 days = 10,000 mg for the course.

The number of tablets needed is therefore:

Number of tablets = total medication needed / strength of each tablet

Number of tablets = 10,000 mg / 250 mg/tablet = 40 tablets.

So, the veterinarian must dispense 40 tablets to the dog owner.

User Keithwill
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