Question

2NaOH H₂SO₄ → Na₂SO₄ + 2H₂O 50 cm³ of a 1,5 -3 solution of NaOH is neutralised by 20 cm³ of H₂SO₄. 1 How many moles of NaOH reacted?

Answer 1

The number of moles of NaOH that reacted can be calculated using the given volume and concentration.

Step-by-step explanation:

The balanced chemical reaction is:

H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄ (aq) + 2H₂O(l)

From the reaction, it can be seen that one mole of H₂SO₄ reacts with two moles of NaOH. Therefore, the number of moles of NaOH reacted can be calculated using the given volume and concentration:

Number of moles of NaOH = volume of NaOH solution (in dm³) * concentration of NaOH (in mol/dm³)

Number of moles of NaOH = 0.050 dm³ * 1.5 mol/dm³

Number of moles of NaOH = 0.075 mol